- 16 cm
- 15 cm
- 17 cm
- 13 cm

Option 1 : 16 cm

**Given**

In Δ ABC P and Q are midpoints of sides AB and AC. If PQ = 8 cm

**Concept used**

Similarity of triangle

**Calculation**

P and Q are midpoints of side AB and AC

Let AB = 2x which makes AP = PB = x

Δ APQ ∼ Δ ABC

∠ A is common, ∠ P = ∠ B and ∠ Q = ∠ C

\(\frac{{AP}}{{AB}} = \frac{{PQ}}{{BC}}\)

\(\frac{x}{{2x}} = \frac{8}{{BC}}\)

BC = 16 cm

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